ln(x) dx
set u = ln(x), dv = dx then we find du = (1/x) dx, v = x
substitute
ln(x) dx = u dv
and use integration by parts
= uv - v du
substitute u=ln(x), v=x, and du=(1/x)dx
= ln(x) x - x (1/x) dx = ln(x) x - dx = ln(x) x - x + C = x ln(x) - x + C. Q.E.D.
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